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Posted on Friday, July 29th, 2011 at 5:57 amWhat is the chance to play the game exactly the same solo twice?
When I was playing a classic solitaire game of an issue interest arises in my mind. Every single solitaire game is different, but what are the chances of ever playing the game exactly the same twice? I I said it must be that of 2369452 or something. So for someone who is very good at math, what are the chances of playing the same game of solitaire twice?
2 + million is not even close! You speak of ALL FIFTY-TWO cards exactly in the same position! Start do the math: even for the first card to be the same, it is only a 1 in 52 chance! Then the second card is 1 in 51. The third card is 1 in 50, then 1-49, 1-48, 1-47 ..... 1-4, then 1-3, then finally when you are dealing with the last 2 cards, you still only a 1 in 2 chances that they will be exactly that order. So ... your final answer is 1 in 52 X 51 X 50 X 49 X 48 X ....... 4 x 3 x 2. It can also be written "one of 52" where "52" is called a factorial. It took me a while to find a site that would actually calculate that for me. The answer is about: 1 of 80,658,175,170,943,878,571,660,636,856, 403,766,975,289,505,440,883,277,824, 000 000 000 000! In case you care, this number may be verbally stated that: "One in 80 unvigintillion, vigintillion 658, 175 novemdecillion, 170 octodecillion, septendecillion 943, 878 sexdecillion, quindecillion 571, 660 quattuordecillion, tredecillion 636, 856 duodecillion, undecillion 403, 766 decillion, 975 quintillion, 289 octillion, septillion 505, 440 sextillion, 883 quintillion, 277 quadrillion, 824 trillion! "To put that in perspective, you'd probably start counting all the atoms on the planet Earth approach and spend that kind of number!
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